What is the solution for y^{''}+5y^'=-6e^{-5x} ?

The solution for y^{''}+5y^'=-6e^{-5x} is y=c_{1}+c_{2}e^{-5x}+(6e^{-5x}x)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+5y^'=-6e^{-5x}

y^{^{''}} + 5 y^{^{'}} = - 6 e^{- 5 x}

y = c_{1} + c_{2} e^{- 5 x} + \frac{6 e ^{- 5 x} x}{5}

Solution steps

y^{''} (x) + 5 y^{'} (x) = - 6 e^{- 5 x}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 5 x} + \frac{6 e ^{- 5 x} x}{5}

y = c_{1} + c_{2} e^{- 5 x} + \frac{6 e ^{- 5 x} x}{5}

y^{^{''}} + 2 y^{^{'}} + 4 y = 3 sin (5 t)

y^{^{''}} - 4 y^{^{'}} - 12 y = 3 cos (x)

y^{^{''}} + y^{^{'}} + 3 y = 2 x - x^{2}

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{e ^{- 3 x}}{x ^{2} + 1}

y^{^{''}} + y^{^{'}} + y = 2 x e^{x}

What is the solution for y^{''}+5y^'=-6e^{-5x} ?
The solution for y^{''}+5y^'=-6e^{-5x} is y=c_{1}+c_{2}e^{-5x}+(6e^{-5x}x)/5