What is the derivative of sin(2θ) ?

The derivative of sin(2θ) is cos(2θ)*2

What is the first derivative of sin(2θ) ?

The first derivative of sin(2θ) is cos(2θ)*2

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derivative of

sin (2 θ)

cos (2 θ) \cdot 2

Solution steps

\frac{d}{d θ} (sin (2 θ))

Apply the chain rule:

cos (2 θ) \frac{d}{d θ} (2 θ)

= cos (2 θ) \frac{d}{d θ} (2 θ)

\frac{d}{d θ} (2 θ) = 2

= cos (2 θ) \cdot 2

\int \frac{e ^{2 x} + 2 e ^{x} + 1}{e ^{x}} d x

\frac{d}{d x} (csc (4 x))

y = 5 x - x^{2}, y = 2 x

\int \frac{5 x x}{1 + x ^{5}} d x

y^{^{''}} - 18 y^{^{'}} + 145 y = 0

What is the derivative of sin(2θ) ?
The derivative of sin(2θ) is cos(2θ)*2
What is the first derivative of sin(2θ) ?
The first derivative of sin(2θ) is cos(2θ)*2