What is the solution for x^{''}+9x=sin(3t) ?

The solution for x^{''}+9x=sin(3t) is x=c_{1}cos(3t)+c_{2}sin(3t)-(tcos(3t))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}+9x=sin(3t)

x^{^{''}} + 9 x = sin (3 t)

x = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{t cos ( 3 t )}{6}

Solution steps

x^{''} (t) + 9 x = sin (3 t)

Solve linear ODE:

x = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{t cos ( 3 t )}{6}

x = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{t cos ( 3 t )}{6}

4 y^{^{''}} - y = e^{\frac{x}{2}} + 2

y^{^{''}} - 4 y = 6 cos (3 t + 3 0^{\circ})

y^{^{''}} - 7 y^{^{'}} + 6 y = 3 e^{t}

y^{^{''}} + 4 y = t e^{3 t} + 3 sin (4 t)

y^{^{''}} + 2 y^{^{'}} - 3 y = e^{x}

What is the solution for x^{''}+9x=sin(3t) ?
The solution for x^{''}+9x=sin(3t) is x=c_{1}cos(3t)+c_{2}sin(3t)-(tcos(3t))/6