What is the solution for (d^2y)/(dx^2)+ay^'-b=0 ?

The solution for (d^2y)/(dx^2)+ay^'-b=0 is y=c_{1}+c_{2}e^{-ax}+(bx)/a

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)+ay^'-b=0

\frac{d ^{2} y}{d x ^{2}} + a y^{^{'}} - b = 0

y = c_{1} + c_{2} e^{- a x} + \frac{b x}{a}

Solution steps

y^{''} (x) + a y^{'} (x) - b = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- a x} + \frac{b x}{a}

y = c_{1} + c_{2} e^{- a x} + \frac{b x}{a}

y^{^{''}} + y^{^{'}} - 6 y = 2 x

2 y^{^{'''}} - 3 y^{^{''}} + y = x^{2} + x

y^{^{''}} + 4 y^{^{'}} + 5 y = 50 x + 13 e^{3 x}

y^{^{''}} + 2 y^{^{'}} + y = \frac{e ^{- x}}{x ^{2}}

y^{^{''}} + 2 y^{^{'}} + y = e^{2 x}

What is the solution for (d^2y)/(dx^2)+ay^'-b=0 ?
The solution for (d^2y)/(dx^2)+ay^'-b=0 is y=c_{1}+c_{2}e^{-ax}+(bx)/a