What is the solution for y^{''}+10y^'+16y=2581cos(5x) ?

The solution for y^{''}+10y^'+16y=2581cos(5x) is y=c_{1}e^{-2x}+c_{2}e^{-8x}+50sin(5x)-9cos(5x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+10y^'+16y=2581cos(5x)

y^{^{''}} + 10 y^{^{'}} + 16 y = 2581 cos (5 x)

y = c_{1} e^{- 2 x} + c_{2} e^{- 8 x} + 50 sin (5 x) - 9 cos (5 x)

Solution steps

y^{''} (x) + 10 y^{'} (x) + 16 y = 2581 cos (5 x)

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{- 8 x} + 50 sin (5 x) - 9 cos (5 x)

y = c_{1} e^{- 2 x} + c_{2} e^{- 8 x} + 50 sin (5 x) - 9 cos (5 x)

y^{^{''}} - 3 y^{^{'}} + 2 y = \frac{e ^{x}}{1 + e ^{x}}

y^{^{''}} + y^{^{'}} + \frac{1}{4} y = e^{x} (sin (3 x) - cos (3 x))

y^{^{''}} - 2 y^{^{'}} + y = \frac{e ^{x}}{( 1 + x ^{2} )}

y^{^{''}} + 3 y^{^{'}} + 2 y = 6 e^{x}

q^{^{''}} + 100 q^{^{'}} + 2500 q = 30

What is the solution for y^{''}+10y^'+16y=2581cos(5x) ?
The solution for y^{''}+10y^'+16y=2581cos(5x) is y=c_{1}e^{-2x}+c_{2}e^{-8x}+50sin(5x)-9cos(5x)