What is the derivative of (4x^2-2x^4) ?

The derivative of (4x^2-2x^4) is 4(4x^2-2x)^3(8x-2)

What is the first derivative of (4x^2-2x^4) ?

The first derivative of (4x^2-2x^4) is 4(4x^2-2x)^3(8x-2)

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\frac{d}{d x} ((4 x^{2} - 2 x)^{4})

4 (4 x^{2} - 2 x)^{3} (8 x - 2)

Solution steps

\frac{d}{d x} ((4 x^{2} - 2 x)^{4})

Apply the chain rule:

4 (4 x^{2} - 2 x)^{3} \frac{d}{d x} (4 x^{2} - 2 x)

= 4 (4 x^{2} - 2 x)^{3} \frac{d}{d x} (4 x^{2} - 2 x)

\frac{d}{d x} (4 x^{2} - 2 x) = 8 x - 2

= 4 (4 x^{2} - 2 x)^{3} (8 x - 2)

t \to 0 lim (\frac{e ^{6 t} - 1}{sin ( t )})

θ \to + 0 lim (\frac{sin ( 8 θ )}{θ})

\int e^{- 9 x} d x

5 ln (x), x ln (x)

\int \frac{1}{3 x ^{2} - 2 x + 5} d x

What is the derivative of (4x^2-2x^4) ?
The derivative of (4x^2-2x^4) is 4(4x^2-2x)^3(8x-2)
What is the first derivative of (4x^2-2x^4) ?
The first derivative of (4x^2-2x^4) is 4(4x^2-2x)^3(8x-2)