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Popular >

y^{''}-y^'-6=0

Solution

y^{^{''}} - y^{^{'}} - 6 = 0

Solution

y = c_{1} e^{t} + c_{2} - 6 t

Solution steps

y^{''} (t) - y^{'} (t) - 6 = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} - 6 t

y = c_{1} e^{t} + c_{2} - 6 t

Graph

Popular Examples

y^{''}+4y^'+4y=(e^{-2x})/(x^3)

y^{^{''}} + 4 y^{^{'}} + 4 y = \frac{e ^{- 2 x}}{x ^{3}}

y^{''}+y^'-6y=-22t+12t^2

y^{^{''}} + y^{^{'}} - 6 y = - 22 t + 12 t^{2}

y^{^{''}} + 4 y = - t^{2}

x^{''}-9x=-13cos(2t)

x^{^{''}} - 9 x = - 13 cos (2 t)

y^{''}+y=xcos(2x)

y^{^{''}} + y = x cos (2 x)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'-6=0 ?
The solution for y^{''}-y^'-6=0 is y=c_{1}e^t+c_{2}-6t