What is the solution for y^{''}+7y^'+6y=24 ?

The solution for y^{''}+7y^'+6y=24 is y=c_{1}e^{-t}+c_{2}e^{-6t}+4

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y^{''}+7y^'+6y=24

y^{^{''}} + 7 y^{^{'}} + 6 y = 24

y = c_{1} e^{- t} + c_{2} e^{- 6 t} + 4

Solution steps

y^{''} (t) + 7 y^{'} (t) + 6 y = 24

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- 6 t} + 4

y = c_{1} e^{- t} + c_{2} e^{- 6 t} + 4

y^{^{'''}} - 4 y^{^{'}} = x e^{2 x} + sin (x) + x^{2}

(d^{2} + 6 d + 10) y = 3 x e^{- 3 x} - 2 e^{3 x} cos (x)

y^{^{''}} + 2 y^{^{'}} - 8 y = 6 e^{- 3 x} - e^{- x}

y^{^{''}} + y = \frac{1}{cos ( t )}

x^{^{''}} + 7 x = t e^{3 t}

What is the solution for y^{''}+7y^'+6y=24 ?
The solution for y^{''}+7y^'+6y=24 is y=c_{1}e^{-t}+c_{2}e^{-6t}+4