What is the solution for v^{''}-16v=2e^{4x} ?

The solution for v^{''}-16v=2e^{4x} is v(x)=c_{1}e^{4x}+c_{2}e^{-4x}+(e^{4x}x)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{''}-16v=2e^{4x}

v^{^{''}} - 16 v = 2 e^{4 x}

v (x) = c_{1} e^{4 x} + c_{2} e^{- 4 x} + \frac{e ^{4 x} x}{4}

Solution steps

v^{''} (x) - 16 v (x) = 2 e^{4 x}

Solve linear ODE:

v (x) = c_{1} e^{4 x} + c_{2} e^{- 4 x} + \frac{e ^{4 x} x}{4}

v (x) = c_{1} e^{4 x} + c_{2} e^{- 4 x} + \frac{e ^{4 x} x}{4}

y^{^{''}} + 2 y^{^{'}} + y = t^{5} e^{- t}

y^{^{''}} + 49 y = 17 sec^{2} (7 t)

y^{^{''}} + 4 y = (5 x^{2} + 4 x - 3) e^{x}

(\frac{1}{2}) y^{^{''}} + y^{^{'}} + 5 y = sin (3 t)

y^{^{''''}} + 25 y^{^{''}} = sin (5 t) + t e^{6 t} + 4

What is the solution for v^{''}-16v=2e^{4x} ?
The solution for v^{''}-16v=2e^{4x} is v(x)=c_{1}e^{4x}+c_{2}e^{-4x}+(e^{4x}x)/4