What is the integral of 0.0018h^2 ?

The integral of 0.0018h^2 is 0.0006h^3+C

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integral of 0.0018h^2

\int 0.0018 h^{2} d h

0.0006 h^{3} + C

Solution steps

\int 0.0018 h^{2} d h

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.0018 \cdot \int h^{2} d h

Apply the Power Rule

: \frac{h ^{3}}{3}

= 0.0018 \cdot \frac{h ^{3}}{3}

Simplify

0.0018 \cdot \frac{h ^{3}}{3} : 0.0006 h^{3}

= 0.0006 h^{3}

Add a constant to the solution

= 0.0006 h^{3} + C

y = e^{3 x}, x = 0, x = 2

\frac{d}{d x} (- x cos (x) - x)

\frac{d}{d x} ((x^{3} + 7 x - 1) (5 x + 2))

x \to 1 lim (\frac{0}{0})

f (x) = x^{2} - 4 x + 3