What is the solution for y^{''}+y=2sin(2t) ?

The solution for y^{''}+y=2sin(2t) is y=c_{1}cos(t)+c_{2}sin(t)-2/3 sin(2t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+y=2sin(2t)

y^{^{''}} + y = 2 sin (2 t)

y = c_{1} cos (t) + c_{2} sin (t) - \frac{2}{3} sin (2 t)

Solution steps

y^{''} (t) + y = 2 sin (2 t)

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) - \frac{2}{3} sin (2 t)

y = c_{1} cos (t) + c_{2} sin (t) - \frac{2}{3} sin (2 t)

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 e^{2 x} + \frac{x}{2}

y^{^{''}} - y^{^{'}} = t^{2}, y (0) = 0, y^{^{'}} (0) = 0

y^{^{''}} + 4 y^{^{'}} + 3 y = 3 x

y^{^{'''}} - y^{^{''}} - y^{^{'}} + y = 7 e^{- t} + 2

y^{^{'''}} + y^{^{''}} = e^{t} + t + 1

What is the solution for y^{''}+y=2sin(2t) ?
The solution for y^{''}+y=2sin(2t) is y=c_{1}cos(t)+c_{2}sin(t)-2/3 sin(2t)