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Popular >

y^{''}-y^'=-4

Solution

y^{^{''}} - y^{^{'}} = - 4

Solution

y = c_{1} e^{t} + c_{2} + 4 t

Solution steps

y^{''} (t) - y^{'} (t) = - 4

Solve linear ODE:

y = c_{1} e^{t} + c_{2} + 4 t

y = c_{1} e^{t} + c_{2} + 4 t

Graph

Popular Examples

y^{''}+b^2y=xcos(ax)

y^{^{''}} + b^{2} y = x cos (a x)

y^{''}-y=cos(x)

y^{^{''}} - y = cos (x)

y^{''}+2y^'-3y=tan(x)

y^{^{''}} + 2 y^{^{'}} - 3 y = tan (x)

y^{''}-10y^'+26y=4,y(0)=3,y^'(0)=15

y^{^{''}} - 10 y^{^{'}} + 26 y = 4, y (0) = 3, y^{^{'}} (0) = 15

(d^2y)/(dx^2)-2(dy)/(dx)+5y=e^xcos(2x)

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 5 y = e^{x} cos (2 x)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'=-4 ?
The solution for y^{''}-y^'=-4 is y=c_{1}e^t+c_{2}+4t