What is the solution for y^{''}+4y^'+3y=8xe^x-6 ?

The solution for y^{''}+4y^'+3y=8xe^x-6 is y=c_{1}e^{-x}+c_{2}e^{-3x}+e^xx-3/4 e^x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4y^'+3y=8xe^x-6

y^{^{''}} + 4 y^{^{'}} + 3 y = 8 x e^{x} - 6

y = c_{1} e^{- x} + c_{2} e^{- 3 x} + e^{x} x - \frac{3}{4} e^{x} - 2

Solution steps

y^{''} (x) + 4 y^{'} (x) + 3 y = 8 x e^{x} - 6

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} e^{- 3 x} + e^{x} x - \frac{3}{4} e^{x} - 2

y = c_{1} e^{- x} + c_{2} e^{- 3 x} + e^{x} x - \frac{3}{4} e^{x} - 2

y^{^{''}} + 3 y^{^{'}} - 10 y = e^{- 5 x}

4 y^{^{''}} - 4 y^{^{'}} + y = e^{\frac{x}{2}} 1 - x

y^{^{''}} - y^{^{'}} = x^{2} e^{x}

y^{^{''}} - 2 y^{^{'}} - 3 y = x + 2

y^{^{''}} - 4 y^{^{'}} + 5 y = e^{3 x} sin (2 x)

What is the solution for y^{''}+4y^'+3y=8xe^x-6 ?
The solution for y^{''}+4y^'+3y=8xe^x-6 is y=c_{1}e^{-x}+c_{2}e^{-3x}+e^xx-3/4 e^x-2