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Popular >

y^{''}+y^'-6=0

Solution

y^{^{''}} + y^{^{'}} - 6 = 0

Solution

y = c_{1} + c_{2} e^{- t} + 6 t

Solution steps

y^{''} (t) + y^{'} (t) - 6 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + 6 t

y = c_{1} + c_{2} e^{- t} + 6 t

Graph

Popular Examples

y^{''}-2y^'+65y=e^xcos(8x)

y^{^{''}} - 2 y^{^{'}} + 65 y = e^{x} cos (8 x)

x^{''}+8x=16cos(4t)

x^{^{''}} + 8 x = 16 cos (4 t)

y^{''}-2y^'+y=x-2-2cos(x)

y^{^{''}} - 2 y^{^{'}} + y = x - 2 - 2 cos (x)

y^{''}-3y^'=xe^{(3x)/4}

y^{^{''}} - 3 y^{^{'}} = x e^{\frac{3 x}{4}}

(d-1)^2y=(e^2x+sin^2(x))

(d - 1)^{2} y = (e^{2} x + sin^{2} (x))

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+y^'-6=0 ?
The solution for y^{''}+y^'-6=0 is y=c_{1}+c_{2}e^{-t}+6t