What is derivative of f(x)=ccos(t)+t^2sin(t) ?

The answer to derivative of f(x)=ccos(t)+t^2sin(t) is (dt)/(dx)=0

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derivative of f(x)=ccos(t)+t^2sin(t)

derivative of

f (x) = c cos (t) + t^{2} sin (t)

\frac{d t}{d x} = 0

Solution steps

f (x) = c cos (t) + t^{2} sin (t)

Treat

t

t (x)

Differentiate both sides:

0 = - c sin (t) \frac{d t}{d x} + 2 t \frac{d t}{d x} sin (t) + cos (t) \frac{d t}{d x} t^{2}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int_{3}^{4} (x + 7 x^{2}) d x

ln (3) \cdot e^{x}

\int x^{3} sin (d) x d x

\frac{d y}{d x} = 2 x cos^{2} (y)

\frac{d}{d x} (\frac{x - 4 1 + x}{x ^{2} - 1})

What is derivative of f(x)=ccos(t)+t^2sin(t) ?
The answer to derivative of f(x)=ccos(t)+t^2sin(t) is (dt)/(dx)=0