What is the solution for 3y^{''}+3y^'-6y=4e^{-2x} ?

The solution for 3y^{''}+3y^'-6y=4e^{-2x} is y=c_{1}e^x+c_{2}e^{-2x}-(4e^{-2x}x)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3y^{''}+3y^'-6y=4e^{-2x}

3 y^{^{''}} + 3 y^{^{'}} - 6 y = 4 e^{- 2 x}

y = c_{1} e^{x} + c_{2} e^{- 2 x} - \frac{4 e ^{- 2 x} x}{9}

Solution steps

3 y^{''} (x) + 3 y^{'} (x) - 6 y = 4 e^{- 2 x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- 2 x} - \frac{4 e ^{- 2 x} x}{9}

y = c_{1} e^{x} + c_{2} e^{- 2 x} - \frac{4 e ^{- 2 x} x}{9}

y^{^{''}} + y = cos (\frac{- t + π}{2})

y^{^{''}} - y^{^{'}} - 6 y = 2 sin (3 x)

(D^{2} + 9) y = 4 cos (3 x)

y^{^{''}} + 2 y^{^{'}} = 2 x + 9 - e - 2 x

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 t^{2} + 4 t e^{2 t} + t sin (2 t)

What is the solution for 3y^{''}+3y^'-6y=4e^{-2x} ?
The solution for 3y^{''}+3y^'-6y=4e^{-2x} is y=c_{1}e^x+c_{2}e^{-2x}-(4e^{-2x}x)/9