What is the solution for y^{''}+4y=9sin(t) ?

The solution for y^{''}+4y=9sin(t) is y=c_{1}cos(2t)+c_{2}sin(2t)+3sin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4y=9sin(t)

y^{^{''}} + 4 y = 9 sin (t)

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 3 sin (t)

Solution steps

y^{''} (t) + 4 y = 9 sin (t)

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 3 sin (t)

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 3 sin (t)

y^{^{''''}} - y = 6 t + cos (t)

y^{^{''}} + y^{^{'}} + y = x e^{- x}

y^{^{''}} - 6 y^{^{'}} + 13 y = 4 e^{3 x}, y (0) = 2, y^{^{'}} (0) = 4

y^{^{''}} - 2 y^{^{'}} + y = e^{- x} cos (x)

y^{^{''}} - y = e^{t}, y (0) = 1, y^{^{'}} (0) = 1

What is the solution for y^{''}+4y=9sin(t) ?
The solution for y^{''}+4y=9sin(t) is y=c_{1}cos(2t)+c_{2}sin(2t)+3sin(t)