What is the solution for y^{''}+4y=3sin(t) ?

The solution for y^{''}+4y=3sin(t) is y=c_{1}cos(2t)+c_{2}sin(2t)+sin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4y=3sin(t)

y^{^{''}} + 4 y = 3 sin (t)

y = c_{1} cos (2 t) + c_{2} sin (2 t) + sin (t)

Solution steps

y^{''} (t) + 4 y = 3 sin (t)

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) + sin (t)

y = c_{1} cos (2 t) + c_{2} sin (2 t) + sin (t)

y^{^{''}} + 100 y^{^{'}} + 2500 y = 30

3 y^{^{''}} - 5 y^{^{'}} - 2 y = 3 e^{2 x}

4 y^{^{''}} - 8 y^{^{'}} = cos (2 x) + 7 x^{2}

y^{^{''}} - 2 y^{^{'}} + y = \frac{4 e ^{x}}{x ^{2} + 1}

y^{^{''}} + y^{^{'}} = x + e^{x} + x^{4}

What is the solution for y^{''}+4y=3sin(t) ?
The solution for y^{''}+4y=3sin(t) is y=c_{1}cos(2t)+c_{2}sin(2t)+sin(t)