What is the solution for (d^2+1)y=csc(x) ?

The solution for (d^2+1)y=csc(x) is y=c_{1}cos(x)+c_{2}sin(x)-xcos(x)+ln(sin(x))sin(x)

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(d^2+1)y=csc(x)

(d^{2} + 1) y = csc (x)

y = c_{1} cos (x) + c_{2} sin (x) - x cos (x) + ln (sin (x)) sin (x)

Solution steps

(d^{2} + 1) y = csc (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - x cos (x) + ln (sin (x)) sin (x)

y = c_{1} cos (x) + c_{2} sin (x) - x cos (x) + ln (sin (x)) sin (x)

2 y^{^{''}} + y^{^{'}} - y = 2 e^{x}

y^{^{''}} + 1.44 y = 24 cos (1.2 x)

y^{^{''}} + y = 5 e^{- 4 x}, y (0) = 0, y^{^{'}} (0) = 0

6 y^{^{''}} - y^{^{'}} - 2 y = 3 sin (10 x)

y^{^{''}} - 7 y^{^{'}} + 12 y = 5 x - 8

What is the solution for (d^2+1)y=csc(x) ?
The solution for (d^2+1)y=csc(x) is y=c_{1}cos(x)+c_{2}sin(x)-xcos(x)+ln(sin(x))sin(x)