What is the solution for y^{''}-7y^'+12y=24 ?

The solution for y^{''}-7y^'+12y=24 is y=c_{1}e^{4t}+c_{2}e^{3t}+2

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y^{''}-7y^'+12y=24

y^{^{''}} - 7 y^{^{'}} + 12 y = 24

y = c_{1} e^{4 t} + c_{2} e^{3 t} + 2

Solution steps

y^{''} (t) - 7 y^{'} (t) + 12 y = 24

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} e^{3 t} + 2

y = c_{1} e^{4 t} + c_{2} e^{3 t} + 2

y^{^{''}} - 6 y^{^{'}} + 9 y = \frac{e ^{3 x}}{x}

y^{^{''}} - 2 y^{^{'}} + 10 y = sin (3 x) + cos (3 x)

y^{^{''}} - 4 y^{^{'}} + 13 y = e^{x} cos (x)

d (x) = 5 (\frac{1}{3})^{x}

y^{^{'''}} + y^{^{''}} = x + e^{- x}

What is the solution for y^{''}-7y^'+12y=24 ?
The solution for y^{''}-7y^'+12y=24 is y=c_{1}e^{4t}+c_{2}e^{3t}+2