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Popular >

y^{''}-8y^'+7=0

Solution

y^{^{''}} - 8 y^{^{'}} + 7 = 0

Solution

y = c_{1} e^{8 t} + c_{2} + \frac{7 t}{8}

Solution steps

y^{''} (t) - 8 y^{'} (t) + 7 = 0

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} + \frac{7 t}{8}

y = c_{1} e^{8 t} + c_{2} + \frac{7 t}{8}

Popular Examples

y^{''}+8y^'+7y=e^{-2x}

y^{^{''}} + 8 y^{^{'}} + 7 y = e^{- 2 x}

y^{''}+3y^'+2y=e^{-5x}(33-36x)

y^{^{''}} + 3 y^{^{'}} + 2 y = e^{- 5 x} (33 - 36 x)

y^{''}-5y^'+6y=x^3+x

y^{^{''}} - 5 y^{^{'}} + 6 y = x^{3} + x

y^{''}-y^'=2x-3

y^{^{''}} - y^{^{'}} = 2 x - 3

y^{''}-y^'=2x+4

y^{^{''}} - y^{^{'}} = 2 x + 4

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-8y^'+7=0 ?
The solution for y^{''}-8y^'+7=0 is y=c_{1}e^{8t}+c_{2}+(7t)/8