What is the derivative of ln(7-x^2) ?

The derivative of ln(7-x^2) is -(2x)/(7-x^2)

What is the first derivative of ln(7-x^2) ?

The first derivative of ln(7-x^2) is -(2x)/(7-x^2)

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derivative of

ln (7 - x^{2})

- \frac{2 x}{7 - x ^{2}}

Solution steps

\frac{d}{d x} (ln (7 - x^{2}))

Apply the chain rule:

\frac{1}{7 - x ^{2}} \frac{d}{d x} (7 - x^{2})

= \frac{1}{7 - x ^{2}} \frac{d}{d x} (7 - x^{2})

\frac{d}{d x} (7 - x^{2}) = - 2 x

= \frac{1}{7 - x ^{2}} (- 2 x)

Simplify

\frac{1}{7 - x ^{2}} (- 2 x) : - \frac{2 x}{7 - x ^{2}}

= - \frac{2 x}{7 - x ^{2}}

n = 0 \sum \infty (\frac{1}{6})^{n + 1}

x \to \infty lim ((1 - \frac{1}{2 x})^{2 x})

\int x^{3} - 6 x d x

(x^{4} e^{- x})^{^{'}}

\frac{\partial}{\partial x} (4 x - 3 x^{4} y^{2})

What is the derivative of ln(7-x^2) ?
The derivative of ln(7-x^2) is -(2x)/(7-x^2)
What is the first derivative of ln(7-x^2) ?
The first derivative of ln(7-x^2) is -(2x)/(7-x^2)