What is the solution for y^{''}-2y^'-3y=e^{2x} ?

The solution for y^{''}-2y^'-3y=e^{2x} is y=c_{1}e^{3x}+c_{2}e^{-x}-1/3 e^{2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-2y^'-3y=e^{2x}

y^{^{''}} - 2 y^{^{'}} - 3 y = e^{2 x}

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{1}{3} e^{2 x}

Solution steps

y^{''} (x) - 2 y^{'} (x) - 3 y = e^{2 x}

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{1}{3} e^{2 x}

y = c_{1} e^{3 x} + c_{2} e^{- x} - \frac{1}{3} e^{2 x}

y^{^{'''}} + 2 y^{^{''}} - 5 y^{^{'}} - 6 y = - sinh (3 x)

y^{^{''}} - 2 y^{^{'}} + 2 y = 3 x + e^{x} tan (x)

y^{^{''}} - 4 y = x

y^{^{''}} - 5 y^{^{'}} + 6 y = x e^{2 x}

y^{^{''}} + y^{^{'}} - 2 y = 4 - 2 x

What is the solution for y^{''}-2y^'-3y=e^{2x} ?
The solution for y^{''}-2y^'-3y=e^{2x} is y=c_{1}e^{3x}+c_{2}e^{-x}-1/3 e^{2x}