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Popular >

y^{''}-5y^'+6=0

Solution

y^{^{''}} - 5 y^{^{'}} + 6 = 0

Solution

y = c_{1} e^{5 t} + c_{2} + \frac{6 t}{5}

Solution steps

y^{''} (t) - 5 y^{'} (t) + 6 = 0

Solve linear ODE:

y = c_{1} e^{5 t} + c_{2} + \frac{6 t}{5}

y = c_{1} e^{5 t} + c_{2} + \frac{6 t}{5}

Popular Examples

x^{''}+2x^'+x=2te^{-t}

x^{^{''}} + 2 x^{^{'}} + x = 2 t e^{- t}

y^{^{''}} + y = 2 t

1/6 y^{''}+6y=tan(6t)-1/2 e^t

\frac{1}{6} y^{^{''}} + 6 y = tan (6 t) - \frac{1}{2} e^{t}

2y^{''}+3y^'-5y=2cos(x)

2 y^{^{''}} + 3 y^{^{'}} - 5 y = 2 cos (x)

y^{''}-4y=e^{-x}

y^{^{''}} - 4 y = e^{- x}

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-5y^'+6=0 ?
The solution for y^{''}-5y^'+6=0 is y=c_{1}e^{5t}+c_{2}+(6t)/5