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Popular >

y^{''}-2y^'+3=0

Solution

y^{^{''}} - 2 y^{^{'}} + 3 = 0

Solution

y = c_{1} e^{2 t} + c_{2} + \frac{3 t}{2}

Solution steps

y^{''} (t) - 2 y^{'} (t) + 3 = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} + \frac{3 t}{2}

y = c_{1} e^{2 t} + c_{2} + \frac{3 t}{2}

Popular Examples

y^{''}+3y^'+2y=xe^{-x}

y^{^{''}} + 3 y^{^{'}} + 2 y = x e^{- x}

y^{''}+4y^'+3y=x^2-2

y^{^{''}} + 4 y^{^{'}} + 3 y = x^{2} - 2

3y^{''}-5y^'+2y=6xe^{-2x}

3 y^{^{''}} - 5 y^{^{'}} + 2 y = 6 x e^{- 2 x}

y^{''}+2y^'+y=sin(x)+7cos(2x)

y^{^{''}} + 2 y^{^{'}} + y = sin (x) + 7 cos (2 x)

y^{''}+4y^'+4y=(7+x)e-2x

y^{^{''}} + 4 y^{^{'}} + 4 y = (7 + x) e - 2 x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-2y^'+3=0 ?
The solution for y^{''}-2y^'+3=0 is y=c_{1}e^{2t}+c_{2}+(3t)/2