What is the solution for ((2x+y+1)dy)/(dx)=1 ?

The solution for ((2x+y+1)dy)/(dx)=1 is y=-(\W((c_{1})/(e^{4x+3)}))/2-2x-3/2

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((2x+y+1)dy)/(dx)=1

\frac{( 2 x + y + 1 ) d y}{d x} = 1

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

Solution steps

\frac{( 2 x + y + 1 ) d y}{d x} = 1

Solve exact ODE:

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

y = - \frac{W ( \frac{c _{1}}{e ^{4 x + 3}} )}{2} - 2 x - \frac{3}{2}

\frac{d}{d z} (\frac{a z ^{2}}{a ^{2} + z ^{2}})

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\frac{\partial}{\partial t} (r \cdot sin (t))

\int a (x) d x

\frac{\partial}{\partial z} (3.5 yz cos (x yz))

What is the solution for ((2x+y+1)dy)/(dx)=1 ?
The solution for ((2x+y+1)dy)/(dx)=1 is y=-(\W((c_{1})/(e^{4x+3)}))/2-2x-3/2