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Popular >

4y^{''}-y^'=1

Solution

4 y^{^{''}} - y^{^{'}} = 1

Solution

y = c_{1} e^{\frac{t}{4}} + c_{2} - t

Solution steps

4 y^{''} (t) - y^{'} (t) = 1

Solve linear ODE:

y = c_{1} e^{\frac{t}{4}} + c_{2} - t

y = c_{1} e^{\frac{t}{4}} + c_{2} - t

Graph

Popular Examples

y^{''}+16y^'+64y=4sin(3x)

y^{^{''}} + 16 y^{^{'}} + 64 y = 4 sin (3 x)

y^{''}+7y^'+10y=15te^{4t}

y^{^{''}} + 7 y^{^{'}} + 10 y = 15 t e^{4 t}

y^{''}-2y^'=e^xsin(x)

y^{^{''}} - 2 y^{^{'}} = e^{x} sin (x)

y^{''}-y=t-2,y(2)=3,y^'(2)=0

y^{^{''}} - y = t - 2, y (2) = 3, y^{^{'}} (2) = 0

y^{''}-y=sin(t)

y^{^{''}} - y = sin (t)

Frequently Asked Questions (FAQ)

What is the solution for 4y^{''}-y^'=1 ?
The solution for 4y^{''}-y^'=1 is y=c_{1}e^{t/4}+c_{2}-t