What is the solution for y^{''}+11y^'+18y=6x ?

The solution for y^{''}+11y^'+18y=6x is y=c_{1}e^{-2x}+c_{2}e^{-9x}+x/3-11/54

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+11y^'+18y=6x

y^{^{''}} + 11 y^{^{'}} + 18 y = 6 x

y = c_{1} e^{- 2 x} + c_{2} e^{- 9 x} + \frac{x}{3} - \frac{11}{54}

Solution steps

y^{''} (x) + 11 y^{'} (x) + 18 y = 6 x

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{- 9 x} + \frac{x}{3} - \frac{11}{54}

y = c_{1} e^{- 2 x} + c_{2} e^{- 9 x} + \frac{x}{3} - \frac{11}{54}

y^{^{''}} - 2 y^{^{'}} + y = x e^{- x} + cos (x)

y^{^{''}} - y^{^{'}} = - 8

y^{^{''}} - 4 y^{^{'}} + 5 y = e^{- t}

x^{^{''}} + 16 x = 160 sin (4 t)

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} - 3 y = 2 e^{4 x}

What is the solution for y^{''}+11y^'+18y=6x ?
The solution for y^{''}+11y^'+18y=6x is y=c_{1}e^{-2x}+c_{2}e^{-9x}+x/3-11/54