What is the solution for y^{'''}-y^{''}+y^'-y=9e^{-x} ?

The solution for y^{'''}-y^{''}+y^'-y=9e^{-x} is y=c_{1}e^x+c_{2}cos(x)+c_{3}sin(x)-9/4 e^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}-y^{''}+y^'-y=9e^{-x}

y^{^{'''}} - y^{^{''}} + y^{^{'}} - y = 9 e^{- x}

y = c_{1} e^{x} + c_{2} cos (x) + c_{3} sin (x) - \frac{9}{4} e^{- x}

Solution steps

y^{'''} (x) - y^{''} (x) + y^{'} (x) - y = 9 e^{- x}

Solve linear ODE:

y = c_{1} e^{x} + c_{2} cos (x) + c_{3} sin (x) - \frac{9}{4} e^{- x}

y = c_{1} e^{x} + c_{2} cos (x) + c_{3} sin (x) - \frac{9}{4} e^{- x}

y^{^{''}} + 4 y = - 20 sin (2 t)

y^{^{''}} - 6 y^{^{'}} + 9 y = 2 e^{x}

x^{^{''}} + 2 x^{^{'}} + 5 x = 1, x^{^{'}} (0) = 0, x (0) = 0

y^{^{''}} + 4 y = 10 cos (2 x) + 15 sin (2 x)

y^{^{''}} - 5 y^{^{'}} = 3 cos (x)

What is the solution for y^{'''}-y^{''}+y^'-y=9e^{-x} ?
The solution for y^{'''}-y^{''}+y^'-y=9e^{-x} is y=c_{1}e^x+c_{2}cos(x)+c_{3}sin(x)-9/4 e^{-x}