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Popular >

y^{''}-y^'=e^x+1

Solution

y^{^{''}} - y^{^{'}} = e^{x} + 1

Solution

y = c_{1} e^{x} + c_{2} + e^{x} x - x

Solution steps

y^{''} (x) - y^{'} (x) = e^{x} + 1

Solve linear ODE:

y = c_{1} e^{x} + c_{2} + e^{x} x - x

y = c_{1} e^{x} + c_{2} + e^{x} x - x

Graph

Popular Examples

y^{''}+3y^'+2y=3t

y^{^{''}} + 3 y^{^{'}} + 2 y = 3 t

y^{''}-5y^'+6y=2te^{2t},y^'(0)=-3

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 t e^{2 t}, y^{^{'}} (0) = - 3

y^{''''}+y=cos(x)

y^{^{''''}} + y = cos (x)

x^{''}+2x^'-8x=12e^{2t}+8t-10

x^{^{''}} + 2 x^{^{'}} - 8 x = 12 e^{2 t} + 8 t - 10

y^{''}-4y^'+5y=4e^{3t},y(0)=2,y^'(0)=7

y^{^{''}} - 4 y^{^{'}} + 5 y = 4 e^{3 t}, y (0) = 2, y^{^{'}} (0) = 7

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'=e^x+1 ?
The solution for y^{''}-y^'=e^x+1 is y=c_{1}e^x+c_{2}+e^xx-x