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Popular >

y^{''}-12y^'+36=0

Solution

y^{^{''}} - 12 y^{^{'}} + 36 = 0

Solution

y = c_{1} e^{12 t} + c_{2} + 3 t

Solution steps

y^{''} (t) - 12 y^{'} (t) + 36 = 0

Solve linear ODE:

y = c_{1} e^{12 t} + c_{2} + 3 t

y = c_{1} e^{12 t} + c_{2} + 3 t

Graph

Popular Examples

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y^{''}+y=tcos(2t)

y^{^{''}} + y = t cos (2 t)

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(d^2y)/(dx^2)+5y=xsin(x)

\frac{d ^{2} y}{d x ^{2}} + 5 y = x sin (x)

y^{''}+25y=4cos(5x)-7e^{5x}

y^{^{''}} + 25 y = 4 cos (5 x) - 7 e^{5 x}

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-12y^'+36=0 ?
The solution for y^{''}-12y^'+36=0 is y=c_{1}e^{12t}+c_{2}+3t