What is the limit as x approaches 0 of ln(1+3x) ?

The limit as x approaches 0 of ln(1+3x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of ln(1+3x)

x \to 0 lim (ln (1 + 3 x))

0

Solution steps

x \to 0 lim (ln (1 + 3 x))

Plug in the value

x = 0

= ln (1 + 3 \cdot 0)

Simplify

ln (1 + 3 \cdot 0) : 0

= 0

\int \frac{1}{x \cdot x - 1} d x

\frac{\partial}{\partial x} (\frac{x + 4}{y + 4})

x \to 2 lim (3 x^{2} - 7 x)

\int \frac{x ^{2}}{x ^{3} + 4} d x

\int \frac{1}{2 - cos ( x )} d x

What is the limit as x approaches 0 of ln(1+3x) ?
The limit as x approaches 0 of ln(1+3x) is 0