What is the solution for y^{''}-2y^{''}-3y=9x+9 ?

The solution for y^{''}-2y^{''}-3y=9x+9 is y=c_{1}cos(sqrt(3)x)+c_{2}sin(sqrt(3)x)-3x-3

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y^{''}-2y^{''}-3y=9x+9

y^{^{''}} - 2 y^{^{''}} - 3 y = 9 x + 9

y = c_{1} cos (3 x) + c_{2} sin (3 x) - 3 x - 3

Solution steps

y^{''} (x) - 2 y^{''} (x) - 3 y = 9 x + 9

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) - 3 x - 3

y = c_{1} cos (3 x) + c_{2} sin (3 x) - 3 x - 3

y^{^{'''}} - 9 y^{^{''}} + 27 y^{^{'}} - 27 y = 7 e^{3 x}

y^{^{''}} + 16 y = 50 e^{3} t, y (0) = 0, y^{^{'}} (0) = 0

4 y^{^{''}} - 8 y^{^{'}} + 5 y = e^{t} tan (\frac{t}{2})

(D^{2} + 1) y = 3 sin (2 t) - 2 cos (2 t)

y^{^{''}} + y^{^{'}} = \frac{1}{cos ( x )}

What is the solution for y^{''}-2y^{''}-3y=9x+9 ?
The solution for y^{''}-2y^{''}-3y=9x+9 is y=c_{1}cos(sqrt(3)x)+c_{2}sin(sqrt(3)x)-3x-3