What is the solution for y^{''}-8y^'-9y=10,y(0)=0,y^'(0)=4 ?

The solution for y^{''}-8y^'-9y=10,y(0)=0,y^'(0)=4 is y=(-3/5+10/9)e^{9t}+3/5 e^{-t}-10/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-8y^'-9y=10,y(0)=0,y^'(0)=4

y^{^{''}} - 8 y^{^{'}} - 9 y = 10, y (0) = 0, y^{^{'}} (0) = 4

y = (- \frac{3}{5} + \frac{10}{9}) e^{9 t} + \frac{3}{5} e^{- t} - \frac{10}{9}

Solution steps

y^{''} (t) - 8 y^{'} (t) - 9 y = 10

Solve linear ODE:

y = (- \frac{3}{5} + \frac{10}{9}) e^{9 t} + \frac{3}{5} e^{- t} - \frac{10}{9}

y = (- \frac{3}{5} + \frac{10}{9}) e^{9 t} + \frac{3}{5} e^{- t} - \frac{10}{9}

y^{^{''}} + y^{^{'}} + 2 y = e^{x}

y^{^{''}} + 2 y = e^{- 2 x} (x^{2} + 1)

y^{^{''}} + 25 y = sin (7 x)

y^{^{''}} + 2 y^{^{'}} + y = g (t - 1), y (0) = 2, y^{^{'}} (0) = 3

y^{^{''}} + 4 y = t^{2} + 4 e^{t}

What is the solution for y^{''}-8y^'-9y=10,y(0)=0,y^'(0)=4 ?
The solution for y^{''}-8y^'-9y=10,y(0)=0,y^'(0)=4 is y=(-3/5+10/9)e^{9t}+3/5 e^{-t}-10/9