What is the solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=2e^{3x}+4x ?

The solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=2e^{3x}+4x is y=c_{1}e^{2x}+c_{2}e^x+e^{3x}+2x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)-3(dy)/(dx)+2y=2e^{3x}+4x

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = 2 e^{3 x} + 4 x

y = c_{1} e^{2 x} + c_{2} e^{x} + e^{3 x} + 2 x + 3

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = 2 e^{3 x} + 4 x

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + e^{3 x} + 2 x + 3

y = c_{1} e^{2 x} + c_{2} e^{x} + e^{3 x} + 2 x + 3

y^{^{''}} - 3 y^{^{'}} = e^{3 x} + 2 x - 1

y^{^{''}} + 2 y^{^{'}} + y = 7 + 75 sin (2 x)

y^{^{''}} + 2 y^{^{'}} - 3 y = (- 4 x^{2} - 4 x + 2) e^{2 x}

y^{^{''''}} + 2 y^{^{''}} + y = 4 + cos (2 t)

y^{^{''}} + 9 y = 4, y (0) = 0, y^{^{'}} (0) = 0

What is the solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=2e^{3x}+4x ?
The solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=2e^{3x}+4x is y=c_{1}e^{2x}+c_{2}e^x+e^{3x}+2x+3