What is the solution for f^'(x)=sqrt(1-2x) ?

The solution for f^'(x)=sqrt(1-2x) is f(x)=-1/3 (1-2x)^{3/2}+c_{1}

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f^'(x)=sqrt(1-2x)

f^{^{'}} (x) = 1 - 2 x

f (x) = - \frac{1}{3} (1 - 2 x)^{\frac{3}{2}} + c_{1}

Solution steps

f^{'} (x) = 1 - 2 x

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 1 - 2 x d x

\int 1 - 2 x d x = - \frac{1}{3} (1 - 2 x)^{\frac{3}{2}} + c_{1}

f (x) = - \frac{1}{3} (1 - 2 x)^{\frac{3}{2}} + c_{1}

x \to \infty lim (x^{2} + 5 x)

\frac{d}{d x} (3 x + 6)

\int (x^{8} - 16)^{9} x^{7} d x

(e^{\frac{t}{2}} - e)^{- \frac{1}{3}}

\frac{\partial}{\partial x} (\frac{e ^{y}}{x + y ^{4}})

What is the solution for f^'(x)=sqrt(1-2x) ?
The solution for f^'(x)=sqrt(1-2x) is f(x)=-1/3 (1-2x)^{3/2}+c_{1}