What is the solution for y^{''}-y=-10t+4 ?

The solution for y^{''}-y=-10t+4 is y=c_{1}e^t+c_{2}e^{-t}+10t-4

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y^{''}-y=-10t+4

y^{^{''}} - y = - 10 t + 4

y = c_{1} e^{t} + c_{2} e^{- t} + 10 t - 4

Solution steps

y^{''} (t) - y = - 10 t + 4

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- t} + 10 t - 4

y = c_{1} e^{t} + c_{2} e^{- t} + 10 t - 4

y^{^{''}} - 10 y^{^{'}} + 25 y = e^{5} x ln (4 + x^{2})

\frac{d ^{2} y}{d x ^{2}} + y = cot (x)

y^{^{''}} + 4 y^{^{'}} + 3 y = 5 e^{- 3 t}, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + 2 y^{^{'}} + 5 y = e^{- t}

x^{^{''}} + 5 x^{^{'}} + 4 x = 5 e^{10 t}

What is the solution for y^{''}-y=-10t+4 ?
The solution for y^{''}-y=-10t+4 is y=c_{1}e^t+c_{2}e^{-t}+10t-4