en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}+265y^'=tan(16x)

Solution

y^{^{'''}} + 265 y^{^{'}} = tan (16 x)

Solution

y = c_{1} + c_{2} cos (265 x) + c_{3} sin (265 x) - \frac{1}{4240} ln (cos (16 x)) + cos (265 x) \cdot \int - \frac{cos ( 265 x ) tan ( 16 x )}{265} d x + sin (265 x) \cdot \int - \frac{sin ( 265 x ) tan ( 16 x )}{265} d x

Solution steps

y^{'''} (x) + 265 y^{'} (x) = tan (16 x)

Solve linear ODE:

y = c_{1} + c_{2} cos (265 x) + c_{3} sin (265 x) - \frac{1}{4240} ln (cos (16 x)) + cos (265 x) \cdot \int - \frac{cos ( 265 x ) tan ( 16 x )}{265} d x + sin (265 x) \cdot \int - \frac{sin ( 265 x ) tan ( 16 x )}{265} d x

y = c_{1} + c_{2} cos (265 x) + c_{3} sin (265 x) - \frac{1}{4240} ln (cos (16 x)) + cos (265 x) \cdot \int - \frac{cos ( 265 x ) tan ( 16 x )}{265} d x + sin (265 x) \cdot \int - \frac{sin ( 265 x ) tan ( 16 x )}{265} d x

Popular Examples

y^{''}-10y^'+9y=e^{2x}

y^{^{''}} - 10 y^{^{'}} + 9 y = e^{2 x}

y^{''}+y^'-6y=e^{2t}+t

y^{^{''}} + y^{^{'}} - 6 y = e^{2 t} + t

y^{'''}-3y^{''}-y^'+3y=1+e^x

y^{^{'''}} - 3 y^{^{''}} - y^{^{'}} + 3 y = 1 + e^{x}

y^{''}-y=2e^{-t},y(0)=0,y^'(0)=0

y^{^{''}} - y = 2 e^{- t}, y (0) = 0, y^{^{'}} (0) = 0

y^{''}+25y=6sin(5x)

y^{^{''}} + 25 y = 6 sin (5 x)

Frequently Asked Questions (FAQ)

What is the solution for y^{'''}+265y^'=tan(16x) ?
The solution for y^{'''}+265y^'=tan(16x) is