What is the answer to solvefor d,d(t)=12t+20 ?

The answer to solvefor d,d(t)=12t+20 is d=(12t+20)/t ;\quad t\ne 0

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solvefor d,d(t)=12t+20

solve for

d, d (t) = 12 t + 20

d = \frac{12 t + 20}{t}; t \neq = 0

Solution steps

d (t) = 12 t + 20

Divide both sides by

t; t \neq = 0

d = \frac{12 t + 20}{t}; t \neq = 0

y^{^{''}} + 2 y^{^{'}} + y = 12 x e^{- x}

2 y^{^{''}} + 5 y^{^{'}} + 4 x = 0

y^{^{''}} - y^{^{'}} = 3 x^{2}

y^{^{''}} - 2 y^{^{'}} + y = 4 x^{2} - 3 + \frac{e ^{x}}{x}

(d^{3} + 4 d) y = e^{x} + sin (x)

What is the answer to solvefor d,d(t)=12t+20 ?
The answer to solvefor d,d(t)=12t+20 is d=(12t+20)/t ;\quad t\ne 0