What is the solution for y^{''}+y=cos(x)sec(x) ?

The solution for y^{''}+y=cos(x)sec(x) is y=c_{1}cos(x)+c_{2}sin(x)+1

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y^{''}+y=cos(x)sec(x)

y^{^{''}} + y = cos (x) sec (x)

y = c_{1} cos (x) + c_{2} sin (x) + 1

Solution steps

y^{''} (x) + y = cos (x) sec (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + 1

y = c_{1} cos (x) + c_{2} sin (x) + 1

y^{^{''}} + y^{^{'}} = 2 + 2 x + x^{2}

y^{^{''}} - 5 y^{^{'}} + 6 y = 5 x - 5

y^{^{''}} - 2 y^{^{'}} - 3 y = 6 t e^{2 t}, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + y = t - 3 sin (2 t), y (0) = 1, y^{^{'}} (0) = - 3

y^{^{''''}} - y = t e^{t} + sin (t)

What is the solution for y^{''}+y=cos(x)sec(x) ?
The solution for y^{''}+y=cos(x)sec(x) is y=c_{1}cos(x)+c_{2}sin(x)+1