What is the solution for 2x^{''}+4x=6t ?

The solution for 2x^{''}+4x=6t is x=c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t)+(3t)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^{''}+4x=6t

2 x^{^{''}} + 4 x = 6 t

x = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{3 t}{2}

Solution steps

2 x^{''} (t) + 4 x = 6 t

Solve linear ODE:

x = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{3 t}{2}

x = c_{1} cos (2 t) + c_{2} sin (2 t) + \frac{3 t}{2}

y^{^{''}} + 3 y^{^{'}} + 2 y = 18 + e x

y^{^{''}} + y^{^{'}} - 2 y = 2 x^{2} - 3 x

y^{^{''}} - 25 y = e^{5 t}

y^{^{''}} + 12 y = 7 e^{2 x}

y^{^{''}} - 14 y^{^{'}} + 49 y = (x + 1) e^{x}

What is the solution for 2x^{''}+4x=6t ?
The solution for 2x^{''}+4x=6t is x=c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t)+(3t)/2