What is the answer to solvefor d,d(t)= 1/2 t^2-10t ?

The answer to solvefor d,d(t)= 1/2 t^2-10t is d=(t-20)/2 ;\quad t\ne 0

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solvefor d,d(t)= 1/2 t^2-10t

solve for

d, d (t) = \frac{1}{2} t^{2} - 10 t

d = \frac{t - 20}{2}; t \neq = 0

Solution steps

d (t) = \frac{1}{2} t^{2} - 10 t

Divide both sides by

t; t \neq = 0

d = \frac{t - 20}{2}; t \neq = 0

y^{^{''}} - 2 y^{^{'}} + y = 4 x^{2} - 7 + x^{- 1} e^{x}

\frac{d ^{2} y}{d x ^{2}} + \frac{d y}{d x} + y = e^{x}

y^{^{''}} - 4 y^{^{'}} + 4 y = 12 x^{2} - 40 x + 42

y^{^{''}} + 6 y^{^{'}} + 73 y = 4 cos (5 x)

y^{^{''}} - 4 y^{^{'}} - 5 = 0

What is the answer to solvefor d,d(t)= 1/2 t^2-10t ?
The answer to solvefor d,d(t)= 1/2 t^2-10t is d=(t-20)/2 ;\quad t\ne 0