What is the solution for y^{''}+16y=5sin(4x) ?

The solution for y^{''}+16y=5sin(4x) is y=c_{1}cos(4x)+c_{2}sin(4x)-(5xcos(4x))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+16y=5sin(4x)

y^{^{''}} + 16 y = 5 sin (4 x)

y = c_{1} cos (4 x) + c_{2} sin (4 x) - \frac{5 x cos ( 4 x )}{8}

Solution steps

y^{''} (x) + 16 y = 5 sin (4 x)

Solve linear ODE:

y = c_{1} cos (4 x) + c_{2} sin (4 x) - \frac{5 x cos ( 4 x )}{8}

y = c_{1} cos (4 x) + c_{2} sin (4 x) - \frac{5 x cos ( 4 x )}{8}

y^{^{''}} + 9 y = cos (x), y (\frac{π}{2}) = - \frac{5}{3}, y^{^{'}} (0) = 5

(D^{2} - 3 D + 2) y = x + 1

4 y^{^{''}} + 4 y + y = 3 x e^{x}

y^{^{''}} + 4 y + 4 = 0

x^{^{''}} + 8 x^{^{'}} + 16 x = e^{- t} sin (4 t)

What is the solution for y^{''}+16y=5sin(4x) ?
The solution for y^{''}+16y=5sin(4x) is y=c_{1}cos(4x)+c_{2}sin(4x)-(5xcos(4x))/8