What is the solution for y^{''}-3y^'+2y=x^2+x ?

The solution for y^{''}-3y^'+2y=x^2+x is y=c_{1}e^{2x}+c_{2}e^x+(x^2)/2+2x+5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-3y^'+2y=x^2+x

y^{^{''}} - 3 y^{^{'}} + 2 y = x^{2} + x

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{x ^{2}}{2} + 2 x + \frac{5}{2}

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = x^{2} + x

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{x ^{2}}{2} + 2 x + \frac{5}{2}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{x ^{2}}{2} + 2 x + \frac{5}{2}

y^{^{''}} - 8 y^{^{'}} + 16 y = \frac{e ^{4 x}}{x}

(2 D^{2} - 3 D + 1) y = csc (2 π x)

d, d (x) = \frac{x ^{2} + 13 x + 42}{x ^{2} - 3 x - 28}

y^{^{''}} - 7 y^{^{'}} = x^{2}

x^{^{''}} + 3 x^{^{'}} + 2 x = 3 cos (2 t)

What is the solution for y^{''}-3y^'+2y=x^2+x ?
The solution for y^{''}-3y^'+2y=x^2+x is y=c_{1}e^{2x}+c_{2}e^x+(x^2)/2+2x+5/2