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Popular >

y^{''}-4y^'+3=0

Solution

y^{^{''}} - 4 y^{^{'}} + 3 = 0

Solution

y = c_{1} e^{4 t} + c_{2} + \frac{3 t}{4}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 3 = 0

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} + \frac{3 t}{4}

y = c_{1} e^{4 t} + c_{2} + \frac{3 t}{4}

Graph

Popular Examples

y^{^{''}} + 3 y = 6 x

y^{''}-3y^'+2=0

y^{^{''}} - 3 y^{^{'}} + 2 = 0

-2y^{''}+7y^'-y-8=-6x^2-2x^3e^x

- 2 y^{^{''}} + 7 y^{^{'}} - y - 8 = - 6 x^{2} - 2 x^{3} e^{x}

y^{''}-y^'-2y=4t^2

y^{^{''}} - y^{^{'}} - 2 y = 4 t^{2}

(d^2y)/(dx^2)+25y=5x^2+x

\frac{d ^{2} y}{d x ^{2}} + 25 y = 5 x^{2} + x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-4y^'+3=0 ?
The solution for y^{''}-4y^'+3=0 is y=c_{1}e^{4t}+c_{2}+(3t)/4