What is the solution for y^{''}-16y=48t-24e^{-4t} ?

The solution for y^{''}-16y=48t-24e^{-4t} is y=c_{1}e^{4t}+c_{2}e^{-4t}-3t+3te^{-4t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-16y=48t-24e^{-4t}

y^{^{''}} - 16 y = 48 t - 24 e^{- 4 t}

y = c_{1} e^{4 t} + c_{2} e^{- 4 t} - 3 t + 3 t e^{- 4 t}

Solution steps

y^{''} (t) - 16 y = 48 t - 24 e^{- 4 t}

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} e^{- 4 t} - 3 t + 3 t e^{- 4 t}

y = c_{1} e^{4 t} + c_{2} e^{- 4 t} - 3 t + 3 t e^{- 4 t}

x^{^{''}} + 2 x^{^{'}} + 50 x = 2 cos (7 t)

y^{^{''}} + y = (cos (x))^{2}

\frac{d ^{2} y}{d t ^{2}} + 4 y = 4 sec^{2} (2 t)

y^{^{''}} - 2 y^{^{'}} + y = e^{- t} ln (t)

y^{^{''}} + 2 y^{^{'}} + 10 y = t cos (t) + e^{t}

What is the solution for y^{''}-16y=48t-24e^{-4t} ?
The solution for y^{''}-16y=48t-24e^{-4t} is y=c_{1}e^{4t}+c_{2}e^{-4t}-3t+3te^{-4t}