What is the solution for y^{''}+25y=5sec(5t) ?

The solution for y^{''}+25y=5sec(5t) is y=c_{1}cos(5t)+c_{2}sin(5t)+1/5 ln(cos(5t))cos(5t)+tsin(5t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+25y=5sec(5t)

y^{^{''}} + 25 y = 5 sec (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{1}{5} ln (cos (5 t)) cos (5 t) + t sin (5 t)

Solution steps

y^{''} (t) + 25 y = 5 sec (5 t)

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{1}{5} ln (cos (5 t)) cos (5 t) + t sin (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{1}{5} ln (cos (5 t)) cos (5 t) + t sin (5 t)

y^{^{''}} + cy - c - k = 0

y^{^{''}} + 4 y^{^{'}} + 4 y = e^{3 x}

y^{^{''}} + y = 3 sin (2 x) + x cos (2 x)

\frac{d ^{2} y}{d x ^{2}} - 8 \frac{d y}{d x} + 159 = 0

y^{^{''}} + 3 y^{^{'}} + 3 y = 6 sin (2 t)

What is the solution for y^{''}+25y=5sec(5t) ?
The solution for y^{''}+25y=5sec(5t) is y=c_{1}cos(5t)+c_{2}sin(5t)+1/5 ln(cos(5t))cos(5t)+tsin(5t)