What is the integral from 0 to sqrt(3 of)x^2-1 ?

The integral from 0 to sqrt(3 of)x^2-1 is 0

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integral from 0 to sqrt(3 of)x^2-1

\int_{0}^{3} x^{2} - 1 d x

0

Solution steps

\int_{0}^{3} x^{2} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{2} d x - \int_{0}^{3} 1 d x

\int_{0}^{3} x^{2} d x = 3

\int_{0}^{3} 1 d x = 3

= 3 - 3

Simplify

= 0

y = sin (x)

(- 3, 9), (2, - 1)

\int ln (x + x^{2} + 1) d x

\int \frac{121 - x ^{2}}{x} d x

What is the integral from 0 to sqrt(3 of)x^2-1 ?
The integral from 0 to sqrt(3 of)x^2-1 is 0