What is the solution for (d^2y)/(dx^2)+4y=3sin(2x) ?

The solution for (d^2y)/(dx^2)+4y=3sin(2x) is y=c_{1}cos(2x)+c_{2}sin(2x)-(3xcos(2x))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)+4y=3sin(2x)

\frac{d ^{2} y}{d x ^{2}} + 4 y = 3 sin (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) - \frac{3 x cos ( 2 x )}{4}

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 4 y = 3 sin (2 x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) - \frac{3 x cos ( 2 x )}{4}

y = c_{1} cos (2 x) + c_{2} sin (2 x) - \frac{3 x cos ( 2 x )}{4}

y^{^{''}} + 4 y = 5 e^{x} - 4 x^{2}

y^{^{''}} + x + y = 0

y^{^{''}} + y = 1, y (0) = 0, y (1) = 0

y^{^{''}} + 12 y^{^{'}} + 27 y = 64 e^{- 1 t}

y^{^{''}} + 4 y = 4 \cdot sec^{2} (2 t)

What is the solution for (d^2y)/(dx^2)+4y=3sin(2x) ?
The solution for (d^2y)/(dx^2)+4y=3sin(2x) is y=c_{1}cos(2x)+c_{2}sin(2x)-(3xcos(2x))/4