What is the derivative of 2sin(x^2) ?

The derivative of 2sin(x^2) is 4xcos(x^2)

What is the first derivative of 2sin(x^2) ?

The first derivative of 2sin(x^2) is 4xcos(x^2)

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derivative of

2 sin (x^{2})

4 x cos (x^{2})

Solution steps

\frac{d}{d x} (2 sin (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (x^{2}))

Apply the chain rule:

cos (x^{2}) \frac{d}{d x} (x^{2})

= cos (x^{2}) \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= 2 cos (x^{2}) \cdot 2 x

Simplify

= 4 x cos (x^{2})

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 7

x \to \infty lim (- 10 e^{- 2 x})

\frac{d y}{d t} = \frac{y}{2}

\int 3 x (x^{2} - 4)^{\frac{1}{2}} d x

\frac{d}{d x} (\frac{e ^{x}}{6 x ^{2} + 1})

What is the derivative of 2sin(x^2) ?
The derivative of 2sin(x^2) is 4xcos(x^2)
What is the first derivative of 2sin(x^2) ?
The first derivative of 2sin(x^2) is 4xcos(x^2)